In the given figure, AB||CD, Angle BAD=30° and Angle ECD=50°, Find Angle CED
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A =
D (Pair of alternate angles)
= 30O
Now, in triangle EDC we have
D = 30O and
C = 50O
So,
CED = 180 – (
C +
D)
= 180 – 30 – 50
=100O
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