In the given figure, AB || CD ∠EAB=105∘ ∠AEC=25∘ and ∠ECD=x∘. Find the value of x.
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Therefore the value of 'x' is 130°.
Given:
AB || CD, ∠EAB=105∘, ∠AEC=25∘ and ∠ECD=x∘.
To Find:
The value of 'x'.
Solution:
This problem can be solved easily as shown below.
Given that: AB║CD, ∠EAB=105∘, ∠AEC=25∘ , and ∠ECD=x∘.
Now draw EF║CD and also EF║AB so AE is a Transverse line.
Let ∠DEF be 'y°'.
⇒ ∠EAB + ∠AEF = 180°
⇒ 105° + 25° + y° = 180°
⇒ y = 180° - 130° = 50°
Now EF║CD then CE is a transverse line.
∴ ∠x + ∠y = 180°
⇒ ∠x + 50°= 180°
⇒ ∠x = 130°
Therefore the value of 'x' is 130°.
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