In the given figure, AB || CD || EF.given AB = 7.5 cm DC = ycmEF = 4.5 cm, BC = x cm.Calculate the values of x and y.
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Answered by
62
In ΔBEF, from basic proportionality theorem.
BD/DF = BC/CE
BD/DF = x/3
or BD= x and DF= 3
In ΔFBA
FD/CD = FB/AB
FD/CD= FD+DB/AB
3/y = x +3/7.5
In ΔBEF
BC/CD= BE/EF
BC/CD= BC=CE/EF
x/y = x+3/4.5
y= 4.5x/ x+3
By subsituting values
3/4.5x/x+3 = x+3/7.5
3x+9/ 4.5x = x+3/7.5
22.5x + 67.5= 4.5x² + 13.5x
4.5x² + 13.5x - 22.5x - 67.5
4.5x² - 9x - 67.5=0
x² -2x -15=0
By factorizing
x² -5x +3x -15=0
(x-5) (x+3)=0
x= 5 and -3
triangle can not be negative so,
y= 4.5 x 5/ 5+3
y=2.8125
BD/DF = BC/CE
BD/DF = x/3
or BD= x and DF= 3
In ΔFBA
FD/CD = FB/AB
FD/CD= FD+DB/AB
3/y = x +3/7.5
In ΔBEF
BC/CD= BE/EF
BC/CD= BC=CE/EF
x/y = x+3/4.5
y= 4.5x/ x+3
By subsituting values
3/4.5x/x+3 = x+3/7.5
3x+9/ 4.5x = x+3/7.5
22.5x + 67.5= 4.5x² + 13.5x
4.5x² + 13.5x - 22.5x - 67.5
4.5x² - 9x - 67.5=0
x² -2x -15=0
By factorizing
x² -5x +3x -15=0
(x-5) (x+3)=0
x= 5 and -3
triangle can not be negative so,
y= 4.5 x 5/ 5+3
y=2.8125
Answered by
4
Answer:
Step-by-step explanation:
Find the slope of the line passing through the given two points.
(i) A(-1.4,-3.7) and B(-2.4,1.3)Find the slope of the line passing through the given two points.
(i) A(-1.4,-3.7) and B(-2.4,1.3)
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