In the given figure, AB || CD || EF. If ∠BCE = 35°
and ∠CEF = 135°, then find the measure of
∠ABC.
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25
angle ABC =80
Step-by-step explanation:
angle CEF +ECD=180
=angle ECD=45
Angle ECD+BCE=angle BCD
=angle BCD=80
angle BCD = angle ABC
ABC = 80
Answered by
16
Given:
∠BCE = 35°
and ∠CEF = 135°
To find:
The measure of ∠ABC.
Solution:
1) Extend the line FE parallel to AB intersects the line BC at O.
2) Then we have a triangle OEC where,
- ∠BCE = 35°
and
- ∠OEC = 180 - ∠CEF
- ∠OEC = 180 - 135
- ∠OEC = 45
and
- ∠ EOC = 180 -∠BCE-∠OEC
- ∠ EOC = 180 -35-45
- ∠ EOC = 180 -80
- ∠ EOC = 100.
now
- ∠ EOB = 180 - 100 ( Linear pair)
- ∠ EOB = 80
3) ∠ EOB = ∠ ABC ( alternate interior angle)
- ∠ ABC = 100
The measure of ∠ABC is 100°
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