Math, asked by lord71, 10 months ago

In the given figure, AB||CD. Find the value of X​

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Answered by bsabishek1010
26

ANSWER:

110°

Step-by-step explanation:

DRAW A LINE FROM EF PARALLEL TO AB AND CD .

ANGLE 180-130= 50.(ANGLE: CEF)

180-(20+50)= X(ANGLE: BAE)

X=110

Answered by Anonymous
55

Answer :

The value of X is 110°

Explanation :

Given, AB is parallel to CD.

=> Draw a line HF parallel to AB and CD

=> HF || AB || CD

Now if HF is parallel to CD then , CE is their transversal,

=> then,

angle DCE + angle CEF = 180°

( since, they are co-interior angles )

=> 130° + y° = 180°

=> y° = 180° - 130°

=> y° = 50°

Now,

If HF || AB and AE is their transversal then ,

angle BAE + angle AEF = 180°

(since, they are co-interior angles)

=> x° + 20° + y° = 180°

=> x° + 20° + 50° = 180°

=> x° = 180° - 70°

=> = 110°

Therefore, The value of X is 110°

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