Question

in the given figure ab||cd find the value of x​

Answer 1

Answer:

here is your answer

x=80

Answer 2

$\large\bf\underline \orange{Given:-}$

• ∠ABO = 135°
• ∠CDO = 145°

$\large\bf\underline \orange{To \: find:-}$

• ∠BOD (x) = ???

$\huge\bf\underline \green{Solution:-}$

we need to draw a line PQ parallel to AB, through x.

Now,

• AB || PQ and AB || CD

SO,

• PQ || CD

Now,

➝ ⠀⠀∠ABO + ∠BOQ = 180°

[ AB || PQ , interior angle on the same side of Transversal BO. ]

➝ ⠀⠀∠ BOQ = 180 - 135

➝ ⠀⠀∠BOQ = 45° ............(i)

Similarly :-

➝ ⠀⠀∠ODC + ∠QOD = 180°

[ PQ || CD, interior angle on the same side of Transversal DO. ]

➝ ⠀⠀∠145 + ∠QOD = 180

➝ ⠀⠀∠QOD = 180 -145

➝ ⠀⠀∠QOD = 35° ...........(ii)

Adding (i) and (ii) ,we get,

➝ ⠀⠀∠BOQ + ∠QOD = 45 +35

➝ ⠀⠀∠x = 80°

So,

x = 80