In the given figure ABǁCD, find the value of x
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AB∥CD,CB is transversal
∴∠OBA=∠OCD (corresponding angles)
∴∠OAB=∠ODC (corresponding angles are equal)
△OAB & △ODC
∴ By AA corollary
△OAB∼△ODC
∴ DCAB = ODOA ⇒ 5.491.83 = 6+xx
⇒x=3m
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