In the given figure AB // CD. Find the
values of x, y and z
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Answer:
given,
AB||CD and pq is transversal
angle QPD +PQR=180°
2x+3x+80°=180°
5x=180-80
x=100/5
x=20
then,
angle CPQ+2x+3x=180°
CPQ+5x=180°
CPQ+5×20=180°
CPQ=180°-100°
=80°
then,
CPR=PRB (alt. int. angle )
80°+40°=z°
z=120°
then,
y+z=180° (linear pair )
y+120°=180°
y=180-120
... y=60°
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