Question

in the given figure AB//CD .PR and QR are angle bisector of BPQ andbPQD respectively.show that PRQ =90°

Answer 1

sum of angle BPQ and angle PQD is 180° because the are Co interior angles
and angles RPQ and RQP are half of them , therefore sum of angle RPQ and RQP is 180/2=90°(eq 1) thus by using angle sum property of triangle we get
RPQ+RQP+QRP=180°
by using eq.1, we get
90°+QRP=180°
therefore QRP=180°-90°
thus, QRP=90°
Hope it helps u :)

Answer 2

this is the answer for this I just changed the name of the figure ......so I think it will help you...