Question

In the given figure AB||CD, the value x is 1) 30° 2)65° 3) 40° 4)75°​

Answer 1

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$\huge\underline\red{given: - }$

From E, draw EF || AB || CD. EF || CD and CE is the transversal.

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[Co-interior angles]

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$\huge\underline\red{solve : - }$

⇒x°+∠CEF=180°⇒∠CEF=(180−x°)

)Again, EF || AB and AE is the transversal.

)Again, EF || AB and AE is the transversal.∠BAE+∠AEF=180°  

  ⇒105°+∠AEC+∠CEF=180°

⇒105°+25°+(180°−x°)=180°

⇒310−x°=180°

Hence, x=130°

Answer: So the value of x is 130