In the given figure AB | CD. Transversal PO intersects AB at E and CD at F. Given, ZCFQ = 47°, the measure of x and y respectively are (2) 30°, 150 (b) 37°, 143 (c) 47°, 133 (d) 399, 141°
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Answer:
AB∣∣CD and PQ is transversal
∠DMQ=100
o
[ Given]
∠DMQ=∠CML=100
o
[ Vertically opposite angles]
∠CML=∠ALP=100
o
[ Corresponding angles]
∠ALP=∠MLB=100
o
[ Vertically opposite angles]
∠CMQ=180−100=80
o
[sum of angle on a straight line is 180^o$$]
∠CMQ=∠LMD=80
o
[ Vertically opposite angles]
∠LMD=∠PLB=80
o
[ Corresponding angles]
∠PLB=∠ALM=80
o
[ Vertically opposite angles]
∴ ∠DMQ=∠CML=∠ALP=∠MLB=100
o
and ∠CMQ=∠LMD=∠ALM=∠PLB=
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