Question

In the given figure, AB || DC. AB = 6cm, DC = 9cm, BC = 5cm and AD = 4cm, find a)the distance between the parallel sides b)the area of the trapezium.​

Answer 1

Answer:

Find the area of a trapezium ABCD whose parallel sides are AB = 19cm, DC = 9cm

Const- Draw a line CE perpendicular to AB

So, DC=AE

FB=AB−AE

EB=19−9

EB=10 cm

ΔCEB is right angle triangle

(BC)

2

=(CE)

2

+(EB)

2

(8)

2

=(CE)

2

+(10)

2

64=(CE)

2

+100

100−64=(CE)

2

36

=CE=6 cm

So, area of trapezium =

2

1

(Sum of side∥side)×h

=

2

1

(9+19)×6

=

2

1

×28×6

=14×6

=84 cm

2

Step-by-step explanation:

Area of a trapezium=

2

1

×(Sum of parallel sides)×distance between them.

=

2

1

×(6+8)×4

=14×2

=28 sq.cm

∴Area of a trapezium=28sq.cms