Question

in the given figure AB=DC and AC=BD.1.is ∆ABC≈∆CDB?2.state the three pairs of congruent parts.3.can we say ∆ABC≈∆DBC?​

Answer 1

Step-by-step explanation:

Third congruent part is the base it is common

Answer 2

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Given = AB = DC

= DB = AC

To prove =

• ΔABC ≈ ΔCDB
• State three pairs of congruent parts.

Proof =

AB = DC (Given)

AC = DB (Given)

BC = BC (Common)

• Hence, by SSS congruence property ,we can say that ΔABC ≈ ΔCDB

-------------> Hence, by CPCT

$\angle{ABC} = \angle{DCB}$

$\angle{BAC} = \angle{BDC}$

$\angle{ABD} = \angle{DCA}$

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