In the given figure, AB // DC and AD // BP. If the area
of trapezium ABCD is 95 sq. cm and the area of
ABCP = 15 sq. cm then find the area of ACAB.Ans: 40 cm
Answers
Answered by
1
Step-by-step explanation:
AB = 7 cm BC = 5cm CD = 15 cm AD = 5 cm
Step-by-step explanation:
in the adjoining figure ABCD is a trapezium ab is parallel to CD and its area is 33 cm²
Area = (1/2)((2x + 1 + x)(x - 4) = 33
=> (3x + 1)(x - 4) = 66
=> 3x² - 12x + x - 4 = 66
=> 3x² - 11x - 70 = 0
=> 3x² - 21x + 10x - 70 = 0
=> 3x(x - 7) + 10(x - 7) =0
=> (3x + 10)(x - 7) = 0
x = 7 x = -10/3 but x can be -ve as x is one of the side
=> x = 7
AB = 7 cm
BC = 7-2 = 5 cm
CD = 2*7 + 1 = 15 cm
AD = BC given
=> AD = 5 cm
AB = 7 cm BC = 5cm CD = 15 cm AD = 5 cm
Answered by
1
Answer:
where is the given figure please give a complete question
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