Question

in the given figure ab // dc and bc// ad find the value of x y z

Answer 1

⚫ Hello friends ‼‼

Here is your answer
➡➡➡➡➡

$< ABD = x$

◼ Given:
AB=DC
BC=AD

x=4/3y
y=3/8y

AB || DC

$< BCD = < ABD = x \\ (alternate \: interior \: angles)$

◼ In ΔBDC

x+y+z=180°

➡ 4/3y+y+z=180°

➡ 7/3y+z=180°

=$\frac{7}{3} \times \frac{3}{8}z + z = 180°$

=$\frac{7}{8}z + z = 180°$

=$z = \frac{180 \times 8}{15}$

z=96°

$y = \frac{3}{8} z$

$= \frac{3}{8} \times 96° \\ = 36°$

$x = \frac{4}{3} \times y$

$= \frac{4}{3} \times 36°$

$= 48°$

◼ I hope this Solution is helpful to you
✔✔✔

➡Thank you ✔✔

Answer 2

Answer:

12346फ़विकडीकेबीसीडी5यूएफजे5895338 HCD7 JHGXV6A689