Question

In the given figure, AB || DC and BCE is a straight line. If angle ABC=50° and angle BAC : ACB = 2 : 3, find angle ACD.

Answer 1

Answer:

Correct option is

C

83o

As  AB || DE, AE is crossing both the parallel lines.

So, ∠BAE=∠AED=40o

In △CDE

∠AED+∠EDC+∠DCE=180

43+40+∠DCE=180

∠DCE=97

As ace is straight line

So, ∠DCE+∠ACD=180

∠ACD=180−97=83

Answer  (C)  83

Explanation:

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