Question

In the given figure, AB || DC and BCE is a straight line.
If ∠ABC = 50° and ∠BAC : ∠ACB = 2:3, find ∠ACD.


Plz solve these answer....
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Answer 1

Answer:

As AB || DE, AE is crossing both the parallel lines.

So, ∠BAE=∠AED=40

o

In △CDE

∠AED+∠EDC+∠DCE=180

43+40+∠DCE=180

∠DCE=97

As ace is straight line

So, ∠DCE+∠ACD=180

∠ACD=180−97=83

Answer (C) 83

Step-by-step explanation:

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