Question

In the given figure, AB || DC. DEDC and DEBA are both isosceles triangles and angle EDC = 31º. Identify the measure of angle AED
(a) 118°
(b) 62°
(c) 57°
(d) 89°​

Answer 1

Answer:

since ab||cd and db is the transversal

abd =31°

and eab is equal to =31°(( isosceles triangle )

so DEA =. 31+31

=62°