In the given figure, AB || DC. If x = 4/3y and y= 3/8z , find x,y,z.
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Solution:-
Given : AB || DC ; x = 4/3y and y = 3/8z.
AB || DC,
⇒ ∠ ABD = ∠ BDC (Alternate angles)
In Δ BDC,
x + y + z = 180°
⇒ 4/3y + 3/8z + z = 180°
⇒ First we will solve the 4/3y.
⇒ 4/3y (since he value of y = 3/8z)
⇒ 4/3 × 3/8z
⇒ 12/24z
⇒ 1/2z
Now, 1/2z + 3/8z + z = 180°
⇒ After taking L.C.M. we get,
⇒ (4z
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