in the given figure AB||DE, then find the value of angle BCD is?
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Answer:
100+x=180(Linear pair)
x=180-100
x=80°=<FBC.
<EDF=<DFB=180.(Corresponding angles).
120+y=180(Linear pair)
y=180-120
y=60°
80+60+<BCD=180°(Sum of angles).
140+<BCD=180°
<BCD=180-140
<BCD=40°
Therefore, <BCD=40°.
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