Question

in the given figure AB divides the angle DAC in ratio 4:1 and ab=db find the value of x​

Answer 1

ANSWER

∠DAC=180°−108°=72°

∠DAB

∠BAC

=

3

1

Given

⇒∠DAB=3∠BAC

∴∠BAC+∠DAB=∠DAC=72°

⇒∠BAC+3∠BAC=72°

⇒4∠BAC=72°

⇒∠BAC=

4

72

=18°

∴∠DAB=3×18°=54°

∴∠DAB=∠BDA=54°(AB=DB)

∴∠ABD=180°−(54°+54°)

=180−108°

=72°

No, ∠DBA=72°=∠BAC+x (Exterio angle)

⇒x=72°−18°=54°

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