Question

In the given figure AB || ED, find x

Answer 1

Answer:

< EDC+ <DCB = 180°

<DCB = 180°- < EDC

<DCB =180°-75°

<DCB = 105°

Since AB is parallel to DC

<DCB = x° (alternate interior angle)

x° = 105°

Answer 2

Answer:

 x = 27

angle CFE =  27 degrees

Step-by-step explanation:

Given

ABC =62

the lines AB and ED are parallel to each other and line segment AF crosses the two lines.

from the diagram angles ABC and angles DCF are corresponding  angles

∴ angles ABC and DCF are equal and = 62.

The angles DCF and ECF make supplementary angles as they are on the same line segment with the common vertex.

∴ DCF + ECF = 180

 62  +  ECF = 180

ECF = 180 -62

ECF = 118

The sum of all angles in a triangle is 180

In triangle ECF

angle ( ECF + CFE + FEC ) = 180

      118 + x + 35 = 180

          x =  180 - 153

          x = 27

∴ angle CFE =  27 degrees

The project code is #SPJ2.