In the given figure, AB > AC. If BO and CO are the bisectors
of B and C respectively, prove that BO > CO.
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In ∆ABC AB>AC
= m of angle ACB>m of angleABC
= 1/2 m of angle ACB>1/2 m of angle ABC
= m of angle OBC<m of angle OCB
= In ∆OBC OB<OC
(Proved)
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