Math, asked by pushpajha80135, 7 months ago

In the given figure, AB I BD, CD I BD and AB = CD.
Prove that :
(i) AABD = ACDB
(ii) AD = CB​

Answers

Answered by anup15416668nnRitik
0

Answer:

Step-by-step explanation:

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anup15416668nnRitik

maheranees

30.07.2018

Math

Secondary School

+5 pts

Answered

In the fig AB = CD, <ABD =<CDB prove that AD=CB

2

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Answers

SachinKrMb

SachinKrMbMaths AryaBhatta

Hey Friends!!

Here is your answer↓⬇

⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇

▶⏩

\huge \bf \sf{It \: is \: given \: that:-)}

↪➡

\bf{AB = CD.}

↪➡

\bf{ \angle \: ABD = \angle \: CDB .}

▶⏩

\huge \bf \sf{To \: prove:-)}

↪➡

\huge \boxed{AD = C B .}

\bf \underline{Now, \: In \: \triangle \: ABD \: and \: \triangle \: CDB.}

\bf{AB = CD ........(given).}

\bf{ \angle \: ABD = \angle \: CDB.......(given).}

\bf{BD = DB.........(common \: side).}

\boxed{ = > by \: SAS \: congruency \: rule}

\huge \bf{ = > \triangle ABD \cong \triangle CDB.}

\boxed{AD = CB.......(CPCT).}

✅✅ Hence, it is proved ✔✔.

\huge \boxed{THANKS}

\huge \bf \underline{Hope \: it \: is \: helpful \: for \: you}

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