In the given figure AB i CD ZAPQ = 50' and
ZPRD = 127. Find the value of x and y.
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PQR=∠APQ (Alternate angle)
x=50
∠PRQ+∠PRD=180
∠PRQ+127
=180
∠PRQ=180
−127
=53
∠PQR+∠QPR+∠PRQ=180
(Angle sum property of trianlge
x+y+53
=180
50
+y+53
=180
y=180
−103
=77
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