Math, asked by afshasheikh526, 8 months ago

In the given figure AB i CD ZAPQ = 50' and
ZPRD = 127. Find the value of x and y.

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Answers

Answered by kargetikavita8
40

PQR=∠APQ (Alternate angle)

x=50

∠PRQ+∠PRD=180

∠PRQ+127

=180

∠PRQ=180

−127

=53

∠PQR+∠QPR+∠PRQ=180

(Angle sum property of trianlge

x+y+53

=180

50

+y+53

=180

y=180

−103

=77

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