IN THE GIVEN FIGURE AB II CD .FIND THE VALUE OF X.......... ALONG With Explanation AND SOLUTION I want ......
Attachments:
Answers
Answered by
2
Consider
AB || CD with AC as transversal
then
angle BAC + ANGLE DCA = 180°
75° + ANGLE DCA = 180°
ANGLE DCA = 105°
Consider triangle CFE
ANGLE C = 105°. (Vertically Opposite Angle)
Now
x° = 180 - (30+105)
x° = 180 - 135
x = 45°
Hope it helped
MarkBrainly
AB || CD with AC as transversal
then
angle BAC + ANGLE DCA = 180°
75° + ANGLE DCA = 180°
ANGLE DCA = 105°
Consider triangle CFE
ANGLE C = 105°. (Vertically Opposite Angle)
Now
x° = 180 - (30+105)
x° = 180 - 135
x = 45°
Hope it helped
MarkBrainly
Similar questions