Question

In the given figure, AB II CD. If ZCAB = 80° and LEFC = 25° then ZCEF = ?​

Answer 1

Answer:

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BAC = DCF ( CORRESPONDING ANGLES ARE EQUAL )

DCF = 80

DCF + FCE = 180 ( LINEAR PAIR )

80 + FCE = 180

FCE = 180 - 80

FCE = 100

IN TRIANGLE CEF

CEF + EFC + FCE = 180 ( ANGLE SUM PROPERTY )

25 + 100 + CEF = 180

CEF = 180 - 125

CEF = 55

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