In the given figure AB II CD, then the value of x is
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GIVEN, AB//CD
SO, BE IS THE TRANSVERSAL.
ANGLE AT C=75°+C=180° (CO-INTERIOR ANGLES)
C=105°
ANGLE C = ANGLE INSIDE TRIANGLE (VERTICALLY OPPOSITE ANGLES)
THEREFORE,
ANGLE INSIDE TRIANGLE+X+30°=180° (ANGLE SUM PROPERTY)
105°+30°+X=180°
X=45°
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