In the given figure, AB is a chord equal to the radius of the given circle with centre O. Find the values of angles 'a'and 'b' .
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1
Answer:
Correct option is
C
105
∘
Given,
AB is a chord of a circle with centre O and AP is the tangent at A and ∠BAP=75
∘
∴∠OAP=90
∘
∴∠OAB=90
∘
−75
∘
=15
∘
So, ∠AOB=180
0
−2(15
0
)
=150
0
∴ Exterior ∠AOB=360
0
−150
0
=210
0
So, ∠ACB=
2
1
×210
0
=105
0
[Since angle subtended by an arc at the centre is double than the angle subtended by it at the remaining part of the circle]
Answered by
1
I don't get how angle AOB and angle DOB would be a linear pair but this is what I got from my teacher tho..I hope this helps
Answer:
a=120, b=120
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