In the given figure, AB is a chord of a circle with centre O. If angle OAB = 50°, then angle ACB is :
(A) 40°
(C) 100
(B) 50°
(D) 25°
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Answer:
A 40°
Step-by-step explanation:
OA=OB (radii of same circle)
Angle OAB=ANGLE OBA (angle opposite to congruent side)
Angle OAB=AngleOBA=50°
IN triangle OAB
ANGLE AOB=80°(remaining angle of a triangle)
Measure arc AB=Measure angle AOB (defination of minor arc)
Measure of arc AB =80°
Angle ACB=1/2*Measure arc AB(Inscribed angle theorem)
=1/2*80°
=40°
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