In the given figure, AB is a chord of a circle with centre O and AB is produced to C such
that BC = OB. Also, CO is joined and produced to meet the circle in
D. If ∠ACD = 25°, then find ∠AOD
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Given BC=OB
ANGLE OBC = ANGLE BCO
ANGLE ABO= 25°+25°=50° (EXTERIOR ANGLE PROPERTY)
AO= BO(RADIUS)
ANGLE ABO=ANGLE BAO
=50°
ANGLE ADO= SUM OF ANGLE OAC AND ANGLE ACO
=50°+25°=75°
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