Question

In the given figure, AB is a chord of a circle
with centre O and AB is produced to C such
that BC =OB. Also, CO is joined and
produced to meet the circle in D. If
ZACD=yº and ZAOD = xº, prove that
x = 3y.​

Answer 1

Answer:

AB is a chord of a circle with centre O AB is produced to C such that BO = BC

CO is joined and produced to meet the circle at D

We shall prove

x ∘

3y

∘

We have

BC=

OB

∠OCB=

∠BOC=

y ∘

[Angles opposite to equal sides are equal ]

△

∠OBA= ∠BOC+ ∠OCB

⇒ ∠OBC=

y ∘

y ∘

2y

∘

OA=OB...[Radii of the same circle ]

∠OAB=

∠OBA

....[Angles opp. To equal sides of a

△

]

=

2y

∘

∠AOD= ∠OAC+ ∠OCA

= 2y

∘

+

y ∘

= 3y

∘

⇒

x ∘

3y

∘

Answer 2

Answer:

x=3y

Step-by-step explanation:

hence prove

I hope u understand this