Question

In the given figure, AB is a chord of a circle with centre O and BOC is a diameter. If OD I AB such that OD = 6 cm, then AC =?
​

Answer 1

Answer:

12 cm

Step-by-step explanation:

Given:  

• AB is a chord of a circle with centre O
• BOC is a diameter.
• OD I AB
• OD=6 cm

By mid point theorem,  in triangle ABC...

OD=1/2 AC

Thus, AC=2OD

         AC=2X6

         AC=12cm

Hope it helps you! Please mark as the brainliest :)