Question

In the given figure, AB is a chord of a circle with centre O and AB is produced to C such that BC = OB. Also, CO is joined and produced to meet the circle in D. If ∠ACD = 25°, then ∠AOD​

Answer 1

Answer:

OB = OC,

∠BOC=∠BCO=y

External ∠OBA=∠BOC+∠BCO=(2y)

Again, OA = OB,

∠OAB=∠OBA=(2y)External

∠AOD=∠OAC+∠ACO

Or x = ∠OAB+∠BCO

Or x = (2 y) + y = 3y

Hence, x = 3y

Step-by-step explanation:

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