Question

In the given figure AB is a diameter of a circle and CD is parallel to AB if angle BAD equals to 30° then angle CAD equals to

Answer 1

<CDA=<BAD=30° (alternate interior angles)

<BDC=90°(Angle subtended on semi-circle is 90°)

so,<CDB+<ADB=<BDC

=>30°+<ADB=90°

=> <ADB=90°-30°

=> <ADB=60°

<CDA+<ADB+<BAD+CAD=180°(sum of opposite angles of a cyclic quadrilateral is 180°)

=>30°+60°+30°+<CAD=180°

=>120°+<CAD=180°

=> <CAD=180°-120°

=> <CAD=60°

so,<CAD=60°.

hope it will help you.

please mark it as brainliest.

Answer 2

answer: angle CAD = 60°

Explanation