Question

In the given figure, AB is a diameter of the circle wuth centre O. DO is parallel to CB and angle DCB = 120°. Calculate :
i) angle DAB
ii) angle DBA
iii) angle DBC
iv) angle ADC

Also prove that triangle AOD ia an equilateral triangle.​

Answer 1

Answer:

i)angle DAB=60degree

ii)angleDBA=30degree

ii)angleDBC=30degree

iii)angleADC=120degree

angle AOD =180-angleDOB

180-120=60degree---(i)

angleODA=angleADB-angleBDO

90degree-30degree

60degree-------(ii)

angleDAO==angleODA-----(opp. angle of opposite sides) -------(iii)

from(i),(ii),(iii)TRIANGLE AOD IS EQUILATERAL TRIANGLE

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