Math, asked by ypriyanshu795, 2 months ago

In the given figure AB is a tangent to the circle at
point B. O is the centre of the circle. If angle AOB =
55°, then angle BAO equals to-​

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Answers

Answered by BharatMandloi
0

Answer:

Step-by-step explanation:

In the given figure AB is a tangent to the circle at

point B. O is the centre of the circle. If angle AOB =

55°, then angle BAO equals to-​

In the given figure AB is a tangent to the circle at

point B. O is the centre of the circle. If angle AOB =

55°, then angle BAO equals to-​

Answered by mathgenius11
1

Step-by-step explanation:

because AB is tangent ye 90° ka angle B par banayegi

so,we can say that,

ANGLE OBA =90°

IN ∆ OBA

ANGLE O +ANGLE B +ANGLE A =180°

55°+90+ANGLE A=180

ANGLE A=180-145

ANGLE A=35°

SO ,ANGLE BAO =35°

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