Question

In the given figure AB is equal to 9cm BD is equals to 6 cm CD is equals to 3 root 3 cm angle ABC equals to angle D equals to 90° calculate AC

Answer 1

Answer:

6=b 9=a 3=d 3=c is the answer of question

Answer 2

Answer:

12cm

Step-by-step explanation:

In ΔBCD,

          $BC^{2}$ = $BD^{2} + DC^{2}$ (by pythagoras theorem)

          $BC^{2}$ = $6^{2} + (3\sqrt{3})^{2}$

          $BC^{2}$ = 36 +27

           BC = $\sqrt{63$cm

In ΔABC,

           $AC^{2} = AB^{2} + BC^{2}$

           $AC^{2} = 9^{2} + (\sqrt{63})^{2}$

          $AC^{2} = 81 + 63\\AC^{2} = 144\\AC = 12cm$