Question

in the given figure AB is parallel to CD. ABE is equal to 120 degree ECD is equal 100 degree and BEC is equal to X find the value of x.

Answer 1

Construction : produce ab to a point h, Mark point of intersection of ec and bh as i
Ebh = 60 degree (leanier pair)
Eih = 100 degree (corresponding angles)
Eib = 80 degree (leanier pair)
In triangle ebi
Ebi = 60 degree
Eib = 80 degree
Bei = x
60+80+x= 180 degree ( asp of triangle)
x = 180-60-80
= 40 degree

Answer 2

here is your answer.