in the given figure ab is parallel to cd and ad is produced to e so that angle bae is equal 125o if angle abc =x angle bcd =y and cde is equal to z
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Let ∠A=2x and ∠B=3x
∠BCD=∠B+∠A (Sum of exterior angle of triangle is equal to sum of two opposite interior angles )
2x+3x=125
∘
5x=125
∘
x=
5
125
∘
=25
∘
∠A=2x=2×25
∘
=50
∘
∠B=3×25
∘
=75
∘
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