in the given figure AB is parallel to CD and transversal of EF cuts them at G and H respectively. if GL and HM are the bisectors of the alternate angles AGH and GHD respectively prove that GL is parallel to HM
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AGH = GHD (AIA)
LGH =GHM ( angles formed by bisectors of equal angles)
But they are AIA
Hence, GL is parallel to HM
LGH =GHM ( angles formed by bisectors of equal angles)
But they are AIA
Hence, GL is parallel to HM
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Answer:Jere is your Answer See the Attachment
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