In the given figure, AB is parallel to CD, EH is parallel to BC, angle BAC = 60, angle DGH = 40.
Find the measures of the angles:
i) AEF
ii) ACD
iii)AFG
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Answer:
Given that ∠BAC=60
o
and ∠DGH=40
o
.
⟹ ∠EAF=60
o
.
Also, given, AE∥DG.
Now, ∠AEF=∠DGH=40
∘
(Corresponding angles).
Then, ∠AFG=∠AEF+∠EAF (Exterior angle property)
⟹ ∠AFG=40
∘
+60
∘
⟹ ∠AFG=100
∘
.
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