in the given figure ab is parallel to CD find the value of x
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123
x = (180-108)+(180-112)
72+68
140°
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72+68
140°
answer plzzzzz mark as brainliest answer plzzzzz
Answered by
58
Solution-
Draw EF|| AB || CD
then, angle 1 + angle 2 = x°
Now , AB || EF and AE is the transversel.
therefore angle 1 + angle BAE = 180° [ co.Int
.angles]
=> angle 1 + 140°= 180°
=> angle 1 = 76°.
Again, EF || CD , and CE is the transversal.
therefore, angle 2 + angle ECD = 180°
=> angle 2 + 116 ° = 180°
=> angle 2 = 64°.
therefore angle 1 + angle 2 = (76° + 64° ) = 140°
Hence, x=140
Draw EF|| AB || CD
then, angle 1 + angle 2 = x°
Now , AB || EF and AE is the transversel.
therefore angle 1 + angle BAE = 180° [ co.Int
.angles]
=> angle 1 + 140°= 180°
=> angle 1 = 76°.
Again, EF || CD , and CE is the transversal.
therefore, angle 2 + angle ECD = 180°
=> angle 2 + 116 ° = 180°
=> angle 2 = 64°.
therefore angle 1 + angle 2 = (76° + 64° ) = 140°
Hence, x=140
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