in the given figure ab is parallel to CD find the value of x
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8
Solution :
i ) Given AB // CD , and AD is the
transversal .
<EDC= <BAD = 57° ---( 1 )
[ Alternate angles ]
ii ) In ∆CDE ,
<C + <EDC + x = 180°
[ angle sum property ]
30° + 57° + x = 180°
=> 87° + x = 180°
=> x = 180° - 87°
x = 93°
••••
i ) Given AB // CD , and AD is the
transversal .
<EDC= <BAD = 57° ---( 1 )
[ Alternate angles ]
ii ) In ∆CDE ,
<C + <EDC + x = 180°
[ angle sum property ]
30° + 57° + x = 180°
=> 87° + x = 180°
=> x = 180° - 87°
x = 93°
••••
Answered by
4
hey mate...
given that AB is parallel to CD
so angle ABE = angle EDC
angle EDC = 57°
now in triangle ECD
angle DEC + EDC + ECD = 180°
57° + 30° + x = 180°
x = 180- 87°
x = 93°
HOPE THIS HELP YOU ☺☺☺
given that AB is parallel to CD
so angle ABE = angle EDC
angle EDC = 57°
now in triangle ECD
angle DEC + EDC + ECD = 180°
57° + 30° + x = 180°
x = 180- 87°
x = 93°
HOPE THIS HELP YOU ☺☺☺
neha656:
dude it helped me a lot ...... tnx
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