Question

in the given figure , AB is parallel to CQ and BC is parallel to PD . prove that angle abc is equal to angle qdp​

Answer 1

Answer:

Proved.

Step-by-step explanation:

Here,

BC||PD

AB||QC

In BC||PD

QC is the transversal

So,

<QDP=<DCB (Corresponding Angles). -I

And in AB||QC

BC is the transversal

So,

<ABC=<DCB (Alternate Interior Angles). -II

Now, from I and II,

we have

<QDP=<DCB = <ABC=<DCB

So, <QDP=<ABC.

Hope you get this!

Answer 2

Step-by-step explanation:

answer

i hope if u like this and

plz give it good stars