Question

In the given figure AB is parallel to DC angle BCE = 80°
and angle BAC = 25°
FIND ANGLE ADC​

Answer 1

Answer:

we know BCE = 80°

BAC= 25 °

BC is perpendicular upon DE to form linear pair

so , 80° + angle BCD = 180°

from this angle BCD = 100 °

now BAC=ACD ( alternate int angles )

ACD =25°

BCD = BCA + ACD

100° = BCA + 25°

100°-25° = BCA = 75 °

now Angle BCA = CAD = 75 °

in ∆ ADC

angle DAC + ACD+ ADC = 180 ° (angle sum Property)

75° + 25° + ADC =180°

100° +ADC =180°

ADC= 80°

Answer 2

Answer:

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Step-by-step explanation:

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