Question

in the given figure AB is parallel to FC angle B=70° and angle FDE=148° . find value of a and b​

Answer 1

Answer:

a=102° and b=70°

Step-by-step explanation:

in the figure,

angle FDC= 180°-148°=32° ( linear pair)

consider triangle ABD,

w.k.t. sum of all the interior angles of triangle is 180°

so, angle A= 180°-32°-70°=78°

consider trapezium ABCF,

as per the property we have angle A and angle c is supplementary,

so 78°+a°=180°

so, a°= 102°

and angle DCF= 180°-102°=78° ( LINEAR PAIR)

in triangle DFC,

b°= 180°-78°-32°= 70°