Question

In the given figure, AB is parellel to DC.....................................

Answer 1

Hi,
Given:AB||DC
/_BDC=35°
/_BAD=80°
So,
x=35°(alternate interior angles)
ADB forms a triangle.
A+y+x=180°(Sum of all angles of triangle is 180)
80°+y+35°=180°
115°+y=180°
y=180°-115°
y=65°
BCD forms a triangle.
(y-30)+z+BDC=180(Sum of all angles of triangle is 180)
(65-30)°+z+35°=180°
35°+z+35°=180°
70°+z=180°
z=180°-70°
z=110°
hope it will help u......
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