Question

In the given figure ab is tangent to a circle with center O. Prove that

Answer 1

Answer:

In △OAB,

OA=AB ....given

∴△OAB is isosceles.

∴∠OBA=∠AOB=x ....(∵OA=AB)

∠OAB+∠ABO+∠AOB=180

o

...Angle sum property o triangle

∴90

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+x+x=180

∘

⇒x=45

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