In the given figure, AB is the diameter of a circle with centre O and OA = 3.5 cm. Find the area of the unshaded region.
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Answer:
area of the big circle
= πr²
= 22 / 7 * 3.5 * 3.5
= 11 * 3.5
= 38.5 cm²
area of small circle
= πr²
= (22/7)(3.5/2)(3.5/2)
= (38.5/4)
= 9.625 cm²
area of triangle Δ CBD
= (1/2)(7)(3.5)
= 3.5 * 3.5
= 12.25 cm²
area of the semi-circle (½ of the big circle)
= 38.5/2
= 19.25 cm²
area unshaded in the semi-circle ACD:
= 19.25 - 9.625
= 9.625 cm²
total area unshaded
= 9.625 + 12.25
= 21.875 cm²
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